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2 years ago

I have a test tmrw pls help

Mathematics

2 answers:

s2008m [1.1K]2 years ago

7 0

So first you would have to find the slope using the two points and the equation: y2-y1/x2-x1, which in this case means you take 6+4/3+1, which would be a slope of 10/4 or 5/2, or 2.5. Using this, we can take a point, use point slope form, and rearrange it. So:

y-6=2.5(x-3)

y-6=2.5x-7.5

-2.5x+y=1.5

Dvinal [7]2 years ago

4 0

The answer is 5x -2y = 3

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The options are<br> 40<br> 80<br> 120<br> 140

Nataly [62]

According to given figure,

$\qquad \sf \dashrightarrow \: \angle ABC + 60° = 180°$

$\qquad \sf \dashrightarrow \: \angle ABC = 180 \degree - 60 \degree$

[ By linear pair ]

$\qquad \sf \dashrightarrow \: \angle ABC = 120 \degree$

now, we can see that :

$\qquad \sf \dashrightarrow \: \angle ABC + \angle BAC = \angle 1$

[ By Exterior angle property of Triangle ]

$\qquad \sf \dashrightarrow \: \angle 1 = 20 \degree + 120 \degree$

$\qquad \sf \dashrightarrow \: \angle 1 = 140 \degree$

4 0

1 year ago

Use the figure to find the measures of the numbered angles,

Galina-37 [17]

Given:

A figure in which a transversal line t intersect the two parallel lines a and b.

To find:

The measure of the numbered angles.

Solution:

If a transversal line intersect the two parallel lines, then

1. Corresponding angles are equal.

2. Alternate interior angles are equal.

3. Alternate exterior angles are equal.

Now,

$m\angle 1+99^\circ=180^\circ$ (Linear pair)

$m\angle 1=180^\circ-99^\circ$

$m\angle 1=81^\circ$

$m\angle 2=99^\circ$ (Vertically opposite angles)

$m\angle 3=\angle 1=81^\circ$ (Vertically opposite angles)

$m\angle 4=99^\circ$ (Corresponding angles)

$m\angle 5=\angle 3=81^\circ$ (Alternate interior angles)

$m\angle 6=99^\circ$ (Alternate exterior angles)

$m\angle 7=\angle 3=81^\circ$ (Corresponding angles)

Therefore, $\angle 1=81^\circ, \angle 2=99^\circ,\angle 3=81^\circ, \angle 4=99^\circ,\angle 5=81^\circ, \angle 6=99^\circ,\angle 7=81^\circ$ .

8 0

2 years ago

Find x. A. 11√6/2 B. 22 C. 33 D. 11√3/2

Phoenix [80]

Answer:

Step-by-step explanation:

using the tangent ratio on the triangle on the right and the exact value

tan60° = $\sqrt{3}$ , then letting the altitude be h

tan60° = $\frac{opposite}{adjacent}$ = $\frac{11\sqrt{6} }{h}$ = $\sqrt{3}$ ( multiply both sides by h )

11 $\sqrt{6}$ = h × $\sqrt{3}$ ( divide both sides by $\sqrt{3}$ )

11 $\sqrt{2}$ = h

using the sine ratio in the triangle on the left and the exact value

sin45° = $\frac{\sqrt{2} }{2}$ , then

sin45° = $\frac{opposite}{hypotenuse}$ = $\frac{h}{x}$ = $\frac{11\sqrt{2} }{x}$ = $\frac{\sqrt{2} }{2}$ ( cross- multiply )

$\sqrt{2}$ × x = 22 $\sqrt{2}$ ( divide both sides by $\sqrt{2}$ )

x = 22

6 0

9 months ago

94b + 48 < b + 54 < 94b + 82

Softa [21]

DATES: The rule amendments will become effective October 29, 1999. Section IV of this release contains information on compliance dates.

3 0

2 years ago

URGENT HELPPP !!!!!! Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!

GaryK [48]

Answer:

(8,-3)

Step-by-step explanation:

I just added 1 to the x value and added 2 to the y value because that was the difference between point A and the midpoint of the segment.

Hope this helps!

3 0

1 year ago