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2 years ago

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The scale for a model is built to represent a real-life skyscraper. If a measurement of 4 cm on the model of the building is equ

ivalent to 36 meters in real-life, what is the scale factor of the model?

1 answer:

Svetlanka [38]2 years ago

5 0

The scale would be 1 centimeter: 9 meters

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Light bulbs of a certain type are advertised as having an averagelifetime of 750 hours. The price of these bulbs is very favorab

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answer 40

Step-by-step explanation:

because you added all together to make one

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3 years ago

Geometry question help

CaHeK987 [17]

Reflection over x-axis

hope that helps

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2 years ago

Scarly bought 3 pounds of cashews. Each pound of cashews cost $2.98. She paid with a $20 bill. How much change did Scarly get ba

pantera1 [17]

Answer:

Answer:

Part a) Mr. Paul bought 14 oz of cashews

Part b) Mr. Paul bought 12 oz of walnuts

Part c) Mr Paul bought 2 oz more of cashews than walnuts

Part d) Mr Paul bought 2 more ounces of nuts than Mrs Toombs

Step-by-step explanation:

Part a) How many ounces of cashews did Mr. Paul buy?

Remember that

To convert lb to oz multiply by 16

we know that

Mr. Paul bought 7/8 lb of cashews <em> I think hope this helps:)</em>

Step-by-step explanation:

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2 years ago

Read 2 more answers

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

2 years ago

Solve : <br>4² ( 4³ )<br>with work shown

stepan [7]

Answer:

1024

Step-by-step explanation:

4²(4³)

4×4(4×4×4)

16(16×4)

16(64)

16×64

=1024

7 0

2 years ago