All categories

2 years ago

What is 0.0004 in its standard form ?

2 answers:

5 0

4 x 10^-4
You move the number forwards till it reaches unit slot in this case but if the number was in the intergers side you would move it back till it gets to the unit slot

OlgaM077 [116]2 years ago

3 0

0.4x10^-3
Adding random characters here.

You might be interested in

Read the numbers and decide what the next number should be. 256 196 144 100 64 36 16

Tatiana [17]

340? TBD add the two numbers.

4 0

3 years ago

Read 2 more answers

4 times a number is 16

andrey2020 [161]

Answer:

4 times 4 equals 16

Step-by-step explanation:

4 times 1= 4

4 times 2= 8

4 times 3= 12

4 times 4= 16

you add 4 after each result.

4 0

2 years ago

Orchestra seats for a Symphony per-

slamgirl [31]

Answer:

The Answer is that Orchestra seats were $15 and Balcony seats were $9.

Step-by-step explanation:

400(x+6) + 250x = 8250

400x + 2400 + 250x = 8250

650x + 2400 = 8250

650x = 5850

x = 9

Proof:

400(15) + 250(9) = 8250

6000 + 2250 = $8,250

7 0

2 years ago

Damian went shopping for a new pair of sneakers. Sales tax where he lives is 5.5%. The price of the pair of sneakers is $48. Fin

mars1129 [50]

Final price including tax: $50.64

5 0

2 years ago

Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col

natali 33 [55]

Answer:

$\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

$\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]$

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

$A^{-1}$ = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = $\left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]$

$A^{-1}$ = $\frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right]$ = $\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

4 0

2 years ago