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2 years ago

Caroline ordered 126 shirts: She plans to decorate the shirts

Mathematics

1 answer:

Rina8888 [55]2 years ago

3 0

Answer:

25 and there a leftpover of 2

Step-by-step explanation:

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Carmen has 75% less money than Anna. How much money does Carmen have if Anna has 256? With explanation pls

Lera25 [3.4K]

Answer: 64 25% of 256 is 64

Step-by-step explanation:

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2 years ago

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You are watching an airplane fly in the distance.The airplane is traveling at altitude of 8 kilometers How far is the airplane f

kotykmax [81]

Answer:

8 km I didn't understand what you are asking

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2 years ago

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The Fort Worth Zoo had 6,195 visitors last week. The zoo is open seven days a

umka21 [38]

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equation:

$7N = 6195$

where $N$ is the number of people that would show up to the zoo on a given day.

Dividing both sides by 7 will give us the answer:

$N = 885$

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2 years ago

Which two points are on the graph of M(a) = - 3/4a-12?

sertanlavr [38]

Answer:

(-16, 0) and (0,-12) are exactly two points on the graph of the given equation.

Step-by-step explanation:

Here, the given expression is : $M(a) = -\frac{3}{4} a-12$

Here, let M(a) = b

⇒The equation becomes $b = -\frac{3}{4} a-12$

Now, check for all the given points for (a,b)

1) FOR (-9,0)

$RHS is -\frac{3}{4} (-9)-12 = -5.25 \neq 0$

Hence, (-9,0) is NOT on the graph.

2) FOR (-16,0)

Here, LHS = b = 0

and $RHS = -\frac{3}{4} (-16)-12 = 12-12 = 0$

Hence, LHS = RHS = 0 So, (-16,0) is on the graph.

3) FOR (0,12)

Here, LHS = b = 12

$RHS is -\frac{3}{4} (0)-12 = -12 \neq 12$

Hence, (0,12) is NOT on the graph.

4) FOR (0,-12)

Here, LHS = b = -12

$RHS is -\frac{3}{4} (0)-12 = -12$

and LHS = RHS = -12

Hence, (0,-12) is on the graph.

Hence, (-16, 0) and (0,-12) are exactly two points on the graph of the given equation.

6 0

2 years ago

Is the set \mathbb{Z} a group under the operation a*b = a - b + ab ? Justify your answer.

Daniel [21]

Answer:

Step-by-step explanation:

Given that *is the binary operation in the sets of integers.

$a*b = a - b + ab$

closure: a-b+ab is again an integer belongs to Z. Hence closure is true.

Associativity: $a*(b*c) = a*(b+c-bc)\\= a-b-c+bc+ab+ac-abc\\= a-b-c +ab+bc+ca-abc$

$(a*b)*c=(a+b-ab)*c\\=a+b-ab-c+ac+bc-abc\\$

The two are not equal. Hence this cannot be a group as associtiavity does not hold good.

7 0

2 years ago