We assume that the dimension 5 has units of feet.
The area of each triangle will be
A = (1/2)bh
where b=2×(5 ft), h=(5 ft)tan(54°)
Then
A = (1/2)(2×5 ft)(5 ft)(tan(54°)
A = 25×tan(54°) ft²
There are 5 such triangles making up this pentagon, so the total area is
total area = 5×25×tan(54°) ft²
≈ 172 ft²
If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
320 i believe... the original answer was 317.52