Answer:
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Inequality :
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
The following is as far as I get:
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1
n−1−(⌊n÷m⌋×(a−b))≥x−α1a
n−(⌊n÷m⌋×(a−b))≥x−α1a + 1
Step-by-step explanation:
$4.00 is my answer.
3x + 5(3) = 27
3x = 27 - 15
3x = 12
x = 12÷3
x = 4
The value of line AL is 21. 51cm
<h3>How to determine the length</h3>
To find line AL,
Using
Sin α = opposite/ hypotenuse to find line AB
Sin 90 = x/ 24
1 = x/24
Cross multiply
x = 24cm
Now, let's find line AC
Sin angle B = line AC/24
Note that to find angle B
angle A + angle B + angle C = 180
But angle B = 2 Angle A
x + 2x + 90 = 180
3x + 90 = 180
3x = 180-90
x = 30°
Angle B = 2 × 30 = 60°
Sin 60 = x/ 24
0. 8660 = x/24
Cross multiply
x = 24 × 0. 8660
x = 20. 78cm
We have the angle of A in the given triangle to be divide into two by the bisector, angle A = 15°
To find line AL, we use
Cos = adjacent/ line AL
Cos 15 = 20. 78/ line AL
Line AL = 20. 78/ cos 15
Line AL = 20. 78 / 0. 9659
Line AL = 21. 51 cm
Thus, the value of line AL is 21. 51cm
Learn more about trigonometry ratio here:
brainly.com/question/24349828
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Answer:
Let R = radius of big circle
r=radius of small circle
A1=Area of small circle
A2=Area of big circle
R=9r
A1=50cm^2
A1=pi*r*2
A2=pi*R^2
A2=pi*(9r)^2
A2=81*pi*r^2
A2=81*A1
A2=4050cm^2
Hence the big circle has area of 4050cm^2
Step-by-step explanation:
