Answer:
- premium: 165 gallons
- water: 120 gallons
Step-by-step explanation:
Let 'a' represent the amount of 95% antifreeze in the mix. Then the amount of water is (285 -a). The mix has this amount of antifreeze in it:
0.95a +0(285 -a) = 0.55(285)
a = 0.55/0.95(285) = 165 . . . gallons of 95%
285 -a = 285 -165 = 120 . . . . gallons of water
There are 120 gallons of water and 165 gallons of premium antifreeze in the mixture.
The number is -1.
5x+2 = x-2
X=-1
all you have to do is subtract 4.37 from 5.08 which is 0.71 seconds
