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2 years ago

Can someone please help me and like show and explain how to get the answer?

Mathematics

1 answer:

lord [1]2 years ago

8 0

It will take layla 11 nigths

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Need help on #7 help if u know how to solve thanks!

mash [69]

7a) 302.5
7b) 302500
Hope this helps! :)

8 0

2 years ago

Read 2 more answers

( 6 , -10 ) y (-15 , 15 ) <br><br><br> Finding slope from two points :)

svet-max [94.6K]

Answer:

-25/21

Step-by-step explanation:

m=(y2-y1)/(x2-x1)=(15-(-10))/(-15-6)=(15+10)/-21=25/-21

5 0

2 years ago

A professor at a university wants to estimate the average number of hours of sleep the students get during exam week. The profes

balandron [24]

Answer:

The sample size is $n = 2$

Step-by-step explanation:

From the question we are told that

The margin of error is E =4.266

The standard deviation is $\sigma = 2.539$

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ] ^2$

=> $n = [\frac{2.58 * 2.539 }{4.266} ] ^2$

=> $n = 2$

6 0

2 years ago

Write three consecutive multiples of 13 in a general form.

S_A_V [24]

Answer:

answer given in step by step...

Step-by-step explanation:

13x+13(x+1)+13(x+2)=312

13x+13x+13+13x+26=312

39x+39=312

39x=312-39

39x=273

x=7

first number=13x=13*7=91

second number=13(8)=104

third number=13(9)=117

5 0

2 years ago

In a geometric sequence, A1 = 0.3 and r=3.Find A12, to the nearest integer

soldi70 [24.7K]

Step-by-step explanation:

We have,

First terms of geometric sequence, a = 0.3

Common ratio, r = 3

It is required to find the 12th term of a GP. The formula of the nth term is given by :

$T_n=ar^{n-1}$

Here, n =12

So,

$T_{12}=0.3\times 3^{12-1}\\\\T_{12}=0.3\times 3^{11}\\\\T_{12}=53144.1$

$T_{12}=53144$

So, the 12th term of the GP is 53144.

8 0

3 years ago