Answer:
0%
Explanation:
This question involves a gene coding for height in pea plants. The allele for tallness (T) is dominant over the allele for shortness (t). This means that allele T will be expressed over allele t in an heterozygous state.
A purebred tall plant will possess genotype: TT while a heterozygous tall plant will possess genotype: Tt. The two parents will produce the following gametes:
TT- T and T
Tt- T and t
Using these gametes in a punnet square (see attached image), the following offsprings with genotypes: TT and Tt in a ratio 1:1 will be produced.
TT offsprings are purebreed tall while Tt offsprings are heterozygous tall. Hence, based on the question, no offsprings of this cross will possess the recessive genotype (tt). This means that 0% of the offsprings of this cross will be short.
Pretty sure its false, will get back to you c:
Recombinant DNA is the answer
How does the whole question go?
The right lung<span> has </span>both<span> more </span>lobes<span> and segments than the left. It is </span>divided into <span>three </span>lobes<span>, an upper, middle, and a lower, by </span>two<span> fissures, one oblique and one horizontal. The upper, horizontal fissure, separates the upper from the middle </span>lobe<span>.</span>