Answer: 1+
Justification:
The ionization energies tell the amount of energy needed to release an electron and form a ion. The first ionization energy if to loose one electron and form the ion with oxidation state 1+, the second ionization energy is the energy to loose a second electron and form the ion with oxidation state 2+, the third ionization energy is the energy to loose a third electron and form the ion with oxidation state 3+.
The low first ionization energy of element 2 shows it will lose an electron relatively easily to form the ion with oxidations state 1+.
The relatively high second ionization energy (and third too) shows that it is very difficult for this atom to loose a second electron, so it will not form an ions with oxidation state 2+. Furthermore, given the relatively high second and third ionization energies, you should think that the oxidation states 2+ and 3+ for element 2 never occurs.
Therefore, the expected oxidation state for the most common ion of element 2 is 1+.
The volume at 100 mmHg : 0.656 L
<h3>
Further explanation</h3>
Boyle's Law
<em>At a constant temperature, the gas volume is inversely proportional to the pressure applied </em>
V₁=3.5 L
P₁=2.5 kPa=18,7515 mmHg
P₂=100 mmHg
The compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.
<h3>What is an ionic compound?</h3>
An ionic compound is a commpound that is composed of ions. Let us note that ionic compounds are always such that the sum of the charges on the ions is zero.
Hence, the compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.
Learn more about ionic compounds:brainly.com/question/9167977
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738.1146 grams, your're welcome
