Switch where the x and y are, then solve for y. f(x) = y.
x = 3y^2 + 6
x-6 = 3y^2
(x-6)/3 = y^2
f^-1(x) = y = sqrt((x-6)/3)
The variable is x, and the coefficient is 4x
1: Perimeter
2:Dimensions
3:scale
We have the expression:
And want to evaluate in y=5, this means we have to replace y in the expression for 5 and calculate the value of the expression, so:
The expression is 30 when y=5.