Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
If you found this helpful please mark brainliest
B as it goes through the correct and average amount of points on the graph, hope this helps
Hello there!
We are given the function:
To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.
Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.
So, we substitute x = 1,2 and 3 in the function.
<u>x</u><u> </u><u>=</u><u> </u><u>1</u>
Recall that any numbers in absolute value are always positive.
<u>x</u><u> </u><u>=</u><u> </u><u>2</u>
<u>x</u><u> </u><u>=</u><u> </u><u>3</u>
Therefore, Range: {-1,1,3}
Let me know if you have any questions!
Topic: Absolute Value Function / Modulus Function
Answer:
Expression for Perimeter: 6x + 6
x = 12 cm
Verify A = 360:
2(12) x (12+3) = 360
24 x 15 = 360
360 = 360
Step-by-step explanation: