Answer:
The outside temperature is -45.8°C
Explanation:
When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).
V1 / T1 = V2 / T2
2.95L/298K = 2.25L / T2
(2.95L/298K ) . T2 = 2.25L
T2 = 2.25L . 298K / 2.95L
T2 = 227.2K
T°K - 273 = T°C
227.2K - 273 = -45.8°C
The attraction mediated flow of water in the narrow tube has been termed as Capillary action. Thus, option A is correct.
The process of flowing up of liquid with the attraction force between the molecules and the surface has been achieved with the surface characteristics.
<h3>Movement of water in a narrow tube</h3>
The surface has the force of attraction with the flowing liquids in the sample. It results in the increased surface interaction, and the liquid flows up in the tube against gravity.
The movement of the liquid in the water through a narrow tube has been termed as capillary action. Thus, option A is correct.
Learn more about movement of water, here:
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