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2 years ago

Need help finding out something, refer to picture

Mathematics

2 answers:

Alja [10]2 years ago

8 0

Answer:

He made a mistake in the second line.

Step-by-step explanation:

He factored out x out of 6-2x and 5+4x, which is not possible because there is not an x in both 6 and 5.

Klio2033 [76]2 years ago

7 0

No x I n 6 ddmrmkebw edd dndnd

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2 years ago

Which number has the same value as 7 X 1/1000

Yuki888 [10]

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12(t + 2) + 4 ≥ - 8

12t + 24 + 4 ≥ - 8

12t + 28 ≥ - 8

12t ≥ - 8 - 28

12t ≥ - 36

t ≥ - 36 ÷ 12

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Solution:

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2 years ago

Read 2 more answers

1.<br> 3z^2+ 8z-3<br> in quadratic formula

tensa zangetsu [6.8K]

Answer:

What grade of math is this?

Step-by-step explanation:

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2 years ago

Solve the following system by any method -8x-8y=0 -8x+2y=-20

iVinArrow [24]

$\fbox{Solution by using Matrix}$

$\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20$

$\text{Rewrite the linear equations above as a matrix}$

$\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right]$

$\text{Apply to Row2 : Row2 + Row1}$

$\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right]$

$\text{Note: The matrix is now in echelon form.}$ $\text{The steps below are for back substitution.}$

$\text{Apply to Row1 : Row1 + 8 Row2}$

$\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right]$

$\text{Therefore, the solution is}$

$x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}$

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2 years ago