Answer:
tan 0= -2.4
sin 0 = 0.42
Step-by-step explanation:
sec 0 = -13/12 => cos 0 = -12/13
cot 0 < 0 => tan 0 < 0
so, the angle is on second quadrant
=> tan 0 = -12/5 = -2.4
=> sin 0 = 5/12 = 0.42
Answer:
f(x) =
Step-by-step explanation:
Let the equation of the function is,
f(x) = mx + b
Here, m = slope of the line
b = y-intercept
From the graph attached,
y-intercept 'b' = 4
Slope =
=
=
Therefore, equation of the function representing the graph will be,
f(x) =
a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )b ) f ` ( x ) =
=
( 2 x³ - 16 x ) / √(x^4 - 16 x²)c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34
<h3>The Graph you need above </h3>
<h3>Step-by-step explaination : </h3>
<h3>Combine 1/3and x.</h3>
y<x/3+1/2
<h3>Use the slope-intercept form to find the slope and y-intercept.</h3><h3 />
Slope: 1/3
y-intercept: 1/2
<h3>Graph a dashed line, then shade the area below the boundary line since y is less</h3><h3>than x/3+1/2.</h3>
<h3>y<x/3+1/2</h3>
Answer:
C
Step-by-step explanation: