2 years ago

Help me with this question

Mathematics

1 answer:

Scilla [17]2 years ago

6 0

Answer:

960 cm³ I think it may be correct

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a(t)=(t−k)(t−3)(t−6)(t+3) is a polynomial function of tt, where kk is a constant. Given that a(2)=0a(2)=0, what is the absolute

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Since $a(2)=0$ , we know that $t-2$ must be a factor of $a(t)$ , so $k=2$ . Then the zeros of $a(t)$ are $t=2,3,6,-3$ , and their product is -108, whose absolute value is 108.

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