All categories

2 years ago

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

Mathematics

1 answer:

jenyasd209 [6]2 years ago

7 0

Answer:

x= -1/3

y= -3 1/3

Step-by-step explanation:

Make both of them into y=Mx+b form

y=-x-3

y=(-x-7)/2

Substitute the x-3 in the first equation for the y in the second one.

x-3=(-x-7)/2

2x-6=-x-7

3x=-1

x=-1/3

Now that we have x, we can solve for y.

y=-x-3

y=-1/3-3

y=-3 1/3

You might be interested in

A manufacturing company makes 1125 items every hour. which or these statements are true ? Check all that apply

Inessa05 [86]

Answer:

I need to see the statements to answer your question

4 0

2 years ago

The ratio of cups of orange juice concentrate to water in a punch recipe is 2 : 6. If Kyle used 36 cups of water, how many cups

pshichka [43]

Step-by-step explanation:

hope this help you have a great day!

3 0

2 years ago

Read 2 more answers

Is finding 9/10-1/2 the same as finding 9/10-1/4-1/4?explain.

zavuch27 [327]

Yes it is the same. 1/4 +1/4 = 1/2. so 9/10-1/2=9/10-1/2

5 0

3 years ago

Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0

3 years ago

HELPPPPPP make sure your right !:)

makvit [3.9K]

To find your constant of variation, you just need to figure out what you multiply the x by in order to get f(x). In other words, what do you multiply the 3 by to get 6? What do you multiply the 7 by to get 14? Another way to think of it is to divide f(x) by the x to get your constant.

4 0

2 years ago