He combustion reaction of hexane:
2 C6H14 + 19 O2 = 12 CO2 + 14 H2O
2 mol C6H14 ---------> 12 mol CO2
x mol C6H14 ---------> 18.4 mol CO2
12 * x = 18.4 * 2
12 x = 36.8
x = 36.8 / 12
x = 3.067 moles of CO2
hope this helps!.
Answer:
Lets Write Down the Given Initial Conditions.
In Order to Solve for the Unknown:
we must use the Ideal Gas Law to Solve for the Second Unknown pressure:
Then Rearrange this equation in a form where P2 can be solved from:
Then Insert the Values from above to solve:
The Answer is : 1830 mmHg considering sig figs
A. 599 mg x 1g/1000mg x 1mole/174.24g = 0.003438 moles
<span>b. 0.003438 moles x 1000 mmoles/mole = 3.438 moles </span>
<span>c. 0.003438 moles/0.741 L = 0.0046 M </span>
<span>d. [K+] = 2 x 0.0046 = 0.0092 M because each mole K2 SO4 yields 2 moles K+ </span>
<span>e. [SO42-] = 0.0046 M </span>
<span>f. 599 mg/0.741 L = 808.4 mg/L = 808 ppm </span>
<span>g. 0.599g/741 ml x 100 ml = 0.08 g/100 ml = 0.08% w/v </span>
<span>h. pK+ = -log [K+] = -log 0.0092 = 2.04 </span>
<span>i. pSO42- = -log [SO42-] = -log 0.0046 = 2.34</span>
Answer:
it would be the second option. It responds to stimuli to help protect an organism and maintain structure