Its like ones true then ones false it goes in that pattern
Answer:
The expression is equal to
The area of the scale drawing is
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
let
z------> the scale factor
x------> the area of the actual room
y-----> the area of the scale drawing
so
we have
substitute and solve for y
Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
Answer:
C. Three
Step-by-step explanation:
We want to solve the equation for n:
14,580 = 20,000(9/10)^n
14580/20000 = 729/1000 = (9/10)^n
(9/10)^3 = (9/10)^n . . . . . . write the left side as a cube
3 = n . . . . . . equate exponents
After year 3, the value will be $14,580.
_____
You can use logarithms to find n:
log(0.729) = n×log(0.9) . . . . . . taking the log of the 2nd line above
log(0.729)/log(0.9) = n = 3