2 years ago

Work out 8^1/3 / 5^-2

Mathematics

1 answer:

kherson [118]2 years ago

8 0

Answer:50

Step-by-step explanation:

Just use a calculator

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Convert 2/3 to a decimal by long division

PilotLPTM [1.2K]

2÷3 3 goes into 2 0 times so add 0 to make 20 3goes into 20 6 time so the answer is 0.6666666

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2 years ago

Cody saves all his nickels. Today he is getting them out of his piggy bank and wrapping them to take to the bank. He finds he ha

erastovalidia [21]

To find the number of wrappers he needs, divide 360 by 40. This is your answer. 360/40 = 9

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2 years ago

Read 2 more answers

Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f

nata0808 [166]

Via Lagrange multipliers:

$L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)$
$L_x=2xy+1+\lambda y=0$
$L_y=x^2+1+\lambda x=0$
$L_\lambda=xy-5=0$

$\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y$
$xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x$

$\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}$
$xy=5\implies y=\pm\sqrt{30}$

At these points, we get local minima of $f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}$ .

- - -

Another way to do this is to make $f(x,y)$ a function independent of $y$ , which is made possible by the constraint.

$xy=5\implies y=\dfrac5x$
$\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x$
$\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}$

and so on.

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2 years ago

WILL GIVE BRAINLIEST IF RIGHT PLZ HELP!!!

Komok [63]

Answer:

-24

Step-by-step explanation:

you're welcome

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2 years ago

Is x=4 solution to equation, x divided by 8 is 2? Show your work and explain how you know

Bezzdna [24]

No, the solution to the problem would be 16. 16/8 equals 2, while 4/8 is 1/2.

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2 years ago