Which of the following functions represent exponential decay?

Mathematics

1 answer:

balu736 [363]2 years ago

4 0

You have exponential decay if the base is a between 0 and 1 and the exponent grows as x grows, or if the base is greater than 1 and the exponents goes to negative infinity as x grows.

The only function that satisfied these requests is the second one: 1/2 is between 0 and 1, and the exponent is x itself.

You might be interested in

levacccp [35]

To solve this problem you can do a proportion
$\frac{x}{215} = \frac{35\%}{100\%}$
to find 'x', we have to cross multiply the numbers.
$215 \times 35$
and
$100 \times x$
this will get you
$7525 = 100x$
to get 'x', we have to divide by 100 on each side
$\frac{7525}{100} = \frac{100x}{100}$

your answer will be
$75.25 = x$
so, Chris must raise 75.25 dollars by himself

3 0

2 years ago

PLS SOLVE THIS!!`1/2p + 7= 3/4p + 9

PtichkaEL [24]

The awnser is P=11/2

8 0

2 years ago

Write a real world situation to explain -$15<$7

Ronch [10]

Jeff has -15$ his gf faith gives him 7.

5 0

2 years ago

Find the area of each shaded sector. Round to the hundredths place.

kati45 [8]

Answer:

200

Step-by-step explanation:vbc i know

3 0

2 years ago

Consider the rational expression (IMAGE ATTACHED)

Keith_Richards [23]

Answer:

3x² is a term in the numerator
x + 1 is a common factor
The denominator has 3 terms

Step-by-step explanation:

You can identify terms and count them before you start factoring. Doing so will identify 3x² as a term in the numerator, and will show you there are 3 terms in the denominator.

When you factor the expression, you get ...

$\dfrac{3x^2-3}{3x^2+2x-1}=\dfrac{3(x^2-1)}{(3x-1)(x+1)}=\dfrac{3(x-1)(x+1)}{(3x-1)(x+1)}$

This reveals a common factor of x+1.

So, the above three observations are true of this rational expression.

3 0

3 years ago