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2 years ago

SOMONE PLEASE HELP ASAP!!!!

Physics

1 answer:

Anna11 [10]2 years ago

7 0

Answer:

from vacuum to air

Explanation:

Refraction is a property of lightwave, in which it changes speed as it passes the boundary between two media.

When light travels from a denser medium to a less dense medium, the light wave speeds up and bends away from the normal.
Also when light travels from a less dense medium to a denser medium, the light wave slows down and bends toward the normal.

The correct option must be from a less dense medium to a denser medium.

density of glass = 2500 kg/m³

density of air = 1.275 kg/m³

density of ice = 919 kg/m³

density of water = 1000 kg/m³

density of plastic = 940 kg/m³

density of vacuum = 6.5 x 10⁻²⁷ kg/m³

The two possible options are;

from ice to water

from vacuum to air

The difference in densities of ice and water is not larger compared to vacuum and air.

If you are required to choose two options, the two options are correct

But if it is only one option, then from vacuum to air is the correct answer.

Therefore, the correct option is from vacuum to air

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If a marathon runner averages 9.51 mi/hr, how long does it take him to run a 26.220-mile marathon. Express your answers in hours

ASHA 777 [7]

Explanation:

Speed of the marathon runner, v = 9.51 mi/hr

Distance covered by the runner, d = 26.220 mile

Let t is the time taken by the marathon runner. We know that the speed of the runner is given by total distance divided by total time taken. Mathematically, it is given by :

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

$t=\dfrac{26.220\ mi}{9.51\ mi/hr}$

t = 2.75 hours

Since, 1 hour = 60 minutes

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2 years ago

Two forces of magnitude 8N and 4N act at right angle to each other. The angle between the resultant and the 8N force is?

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1 year ago

A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t

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Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

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$V_{net} = v_{bird} - v_{wind}$

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Part b)

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$T = t_1 + t_2$

$T = 20 + 7.7 = 27.7 min$

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$T = 22.22 min$

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3 years ago

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Answer:

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Question 2)

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