Answer:
x = 6
Step-by-step explanation:
<em>If </em><em>two secants</em><em> are drawn from</em><em> a point outside </em><em>the circle, then the </em><em>product</em><em> of the lengths of</em><em> one secant </em><em>and its</em><em> external segment</em><em> equals the </em><em>product </em><em>of the lengths of</em><em> the other secant </em><em>and its</em><em> external segment</em><em> </em>
Let us solve the question.
∵ There is a circle in the given figure
∵ There are two secants intersected at a point outside the circle
∵ The length of one of them = 8
∵ The length of its external segment = x
∵ The length of the other secant = 4 + 8 = 12
∵ The length of its external segment = 4
→ By using the rule above
∴ 8 × x = 12 × 4
∴ 8x = 48
→ Divide both sides by 8
∴ x = 6
Uhhh yeah me neither!! 3.14 yes!!! it’s pie
Answer:
To find the area of she shaded part we first need to find the total of the area.
L x W
8 x 5 = 40 is the total area
Now we need to find the area of the non - shaded part
Since it is a square all sides are equal the short lines sticking from the sides indicate that
2 x 2 = 4
Now we subtract the total area from the non shaded area.
40 - 4 = 36
(x, y) = ( cos 45, sin 45) =
![=\text{ (}\frac{\sqrt[]{2}}{2}\text{ , }\frac{\sqrt[]{2}}{2}\text{ )}](https://tex.z-dn.net/?f=%3D%5Ctext%7B%20%28%7D%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%5Ctext%7B%20%2C%20%7D%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%5Ctext%7B%20%29%7D)
The correct option is A
