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2 years ago

Can mixtures and compounds be separated into their elements? If so which?

Chemistry

1 answer:

Mnenie [13.5K]2 years ago

8 0

Answer:

The individual components of a mixture can be physically separated from each other. Chemical compounds are very different from mixtures: The elements in a chemical compound can only be separated by destroying the compound.

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. Which information is NOT included in each square of the periodic table in your text? a. atomic number c. melting point b. chem

azamat

The correct answer is melting point

6 0

3 years ago

A mineral that contains silicon and oxygen

Sergio [31]

<span>Hey there!
Great question:)

Answer:Silicates, this is a mineral that contains silicon and oxygen!

I hope this helps;)
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3 0

2 years ago

The activation energy for a reaction is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a catalyst. If t

11111nata11111 [884]

Answer:

The catalyzed reaction will take 2.85 seconds to occur.

Explanation:

The activation energy of a reaction is given by:

$k = Ae^{-\frac{E_{a}}{RT}}$

For the reaction without catalyst we have:

$k_{1} = Ae^{-\frac{E_{a_{1}}}{RT}}$ (1)

And for the reaction with the catalyst:

$k_{2} = Ae^{-\frac{E_{a_{2}}}{RT}}$ (2)

Assuming that frequency factor (A) and the temperature (T) are constant, by dividing equation (1) with equation (2) we have:

$\frac{k_{1}}{k_{2}} = \frac{Ae^{-\frac{E_{a_{1}}}{RT}}}{Ae^{-\frac{E_{a_{2}}}{RT}}}$

$\frac{k_{1}}{k_{2}} = e^{\frac{E_{a_{2}} - E_{a_{1}}}{RT}$

$\frac{k_{1}}{k_{2}} = e^{\frac{59.0 \cdot 10^{3}J/mol - 184 \cdot 10^{3} J/mol}{8.314 J/Kmol*600 K} = 1.31 \cdot 10^{-11}$

Since the reaction rate is related to the time as follow:

$k = \frac{\Delta [R]}{t}$

And assuming that the initial concentrations ([R]) are the same, we have:

$\frac{k_{1}}{k_{2}} = \frac{\Delta [R]/t_{1}}{\Delta [R]/t_{2}}$

$\frac{k_{1}}{k_{2}} = \frac{t_{2}}{t_{1}}$

$t_{2} = t_{1}\frac{k_{1}}{k_{2}} = 6900 y*1.31 \cdot 10^{-11} = 9.04 \cdot 10^{-8} y*\frac{365 d}{1 y}*\frac{24 h}{1 d}*\frac{3600 s}{1 h} = 2.85 s$

Therefore, the catalyzed reaction will take 2.85 seconds to occur.

I hope it helps you!

4 0

2 years ago

Why it is advisided to freshly prepare the ferrous sulphate solution for experiment

chubhunter [2.5K]

Here is a site my buddie has to help you. Well co-owner..
https://www.quora.com/Why-is-fresly-prepared-FeSO4-required-for-the-ring-test

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2 years ago

__ P4(s) + __ O2(g) → __ P4O10(s) To balance this reaction equation, first write correct formulas for the reactants and products

Vedmedyk [2.9K]

Answer:

P4(s) + 5 O2 (g)→ P4O10

Explanation:

If we desire to write a balanced chemical reaction equation, the rule of thumb is simple; the number of atoms of each element on the right hand side of the reaction equation must be the same as the number of atoms of the same element on the left hand side of the reaction equation. Once this condition is satisfied, the reaction equation is said to be balanced.

As we can see, we need one mole of P4 and five moles of O2 to produce one mole of P4O10.

8 0

3 years ago