Answer:
least common multiple would be 2
I’m assuming 9? There isn’t a question so
Answer:
0.3285
Step-by-step explanation:
This problem involves Geometric probability distribution because experiment is repeated different number of times until success is achieved.
we have to find P(X≥4). It can be written as P(X≥4)=1-P(X<4)=1-P(X≤3)
P(X≤3)=?
Using Geometric probability distribution
P(X=n)=p^x*q^n-1
P(X≤3)=P(X=1)+P(X=2)+P(X=3)
Here p=0.31,
P(X≤3)=0.31^1*0.69^0+0.31^2*0.69^1+0.31^3*0.69^2)=0.6715
P(X≥4)=1-P(X≤3)=1-0.6715=0.3285
The probability that the first strawberry candy chosen from a bag will be, at LEAST, the fourth candy chosen overall is 32.85%.
Answer:
She will need to purchase 16 rolls of ribbon
Step-by-step explanation:
Step 1: Express the total length of ribbon
Use the expression below;
T=R×N
where;
T=total length of ribbon Ruby has
R=length per roll
N=number of rolls
In our case;
T=120 meters, but since 1 meter=3.28084 feet
T=(120×3.28084)=393.7008 feet
R=25 feet
N=n
replacing;
393.7008 =25×n
n=393.7008/25
n=15.748 rounded up=16
She will need to purchase 16 rolls of ribbon