Answer:
Step-by-step explanation:
Given
Required
Write in Standard Form
To start with; the two monomials have to be multiplied together;
Split the numerator and the denominator
Multiply Like terms
Divide 9 by 3 to give 3
Divide n³ by n to n²
Split fraction
From laws of indices;
becomes
Multiply all together
Answer:
c
Step-by-step explanation:
i just used a calculator lol
Answer:
Y = [-6 6 6 -6]
Step-by-step explanation:
From the given matrices
If X - 2Y = Z
b - 2c = a ... 1
a -2d = c ...2
4+2a = 16.... 3
a + 2b = b .... 4
From3 ;
2a = 16-4
2a = 12
a = 6
From 4;
a + 2b - b = 0
a+b = 0
a = -b
6 = -b
b = -6
From1;
b - 2c = a
-6 - 2c = 6
-2c = 12
c = -6
also
a - 2d = c
6-2d = -6
-2d = -6-6
-2d = -12
d = 6
Hence the matrices Y = [-6 6 6 -6]
The result of the respective questions are:
- This chi-square test only takes into consideration one variable.
- The type of chi-square test this is is a Goodness of Fit
- df= 3
- NO
<h3>How many variables are involved in the chi-square test?</h3>
a)
This chi-square test only takes into consideration one variable.
b)
The type of chi-square test this is, is a Goodness of Fit
To test the hypothesis, we must determine whether the actual data conform to the assumed distribution.
The "Goodness-of-Fit" test is a statistical hypothesis test that determines how well the data that was seen resembles the data that was predicted.
c)
Parameter
n = 4
Therefore
Degrees of freedom
df= n - 1
df= 4 - 1
df= 3
d)
In conclusion
Parameters
df = 3
Hence
Critical value = 7.814728
Test statistic = 6.6
Test statistic < Critical value, .
NO, the result of this test is not statistically significant.
Read more about Probability
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To solve this problem, let us recall that the formula for
probability is:
Probability = total number of successful events / total
events
Where in this case, an event is considered to be successful
if the sum is 3 on the pair of six sided dice.
First, let us calculate for the total number of events. There
are 6 numbers per dice, therefore the total number of combinations is:
total events = 6 * 6 = 36
Next, we calculate for the total number of combinations
that result in a sum of 3. We can identify that there are only two cases that
result in sum of 3. That is:
1st case: first dice rolls 1, second dice
rolls 2
2nd case: first dice rolls 2, second dice
rolls 1
Hence, total number of successful events = 2. Therefore the
probability is:
Probability = 2 / 36 = 1 / 18 = 0.0556 = 5.56%
