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2 years ago

A mole of oxygen and a mole of hydrogen (at STP) have all of the following in common EXCEPT

Chemistry

1 answer:

Drupady [299]2 years ago

8 0

Answer:

Root mean squared velocity is different.

Explanation:

Hello!

In this case, since we have a mixture of oxygen and nitrogen at STP, which is defined as a condition whereas T = 298 K and P = 1 atm, we can infer that these gases have the same temperature, pressure, volume and moles but a different root mean squared velocity according to the following formula:

$v_{rms}=\sqrt{\frac{3RT}{MM} }$

Since they both have a different molar mass (MM), nitrogen (28.02 g/mol) and oxygen (32.02 g/mol), thus we infer that nitrogen would have a higher root mean squared velocity as its molar mass is less than that of oxygen.

Best regards!

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The equilibrium constant Kc for the reaction

PIT_PIT [208]

Answer:

[N2] = 0.3633M

[H2] = 1.090M

[NH3] = 0.2734M

Explanation:

Based on the reaction of the problem, Kc is defined as:

Kc = 0.159 = [NH3]² / [N2] [H2]³

<em>Where [] are the equilibrium concentrations.</em>

The initial concentrations of the reactants is:

N2 = 1.00mol / 2.00L = 0.500M

H2 = 3.00mol / 2.00L = 1.50M

When the equilibrium is reached, the concentrations are:

[N2] = 0.500M - X

[H2] = 1.50M - 3X

[NH3] = 2X

<em>Where X is reaction quotient</em>

Replacing in the Kc equation:

0.159 = [2X]² / [0.500 - X] [1.50 - 3X]³

0.159 = 4X² / 1.6875 - 13.5 X + 40.5 X² - 54 X³ + 27 X⁴

0.268313 - 2.1465 X + 6.4395 X² - 8.586 X³ + 4.293 X⁴ = 4X²

0.268313 - 2.1465 X + 2.4395 X² - 8.586 X³ + 4.293 X⁴ = 0

Solving for X:

X = 0.1367. Right solution.

X = 1.8286. False solution. Produce negative concentrations

Replacing:

[N2] = 0.500M - 0.1367M

[H2] = 1.50M - 3*0.1367M

[NH3] = 2*0.1367M

The equilibrium concentrations are:

3 0

2 years ago

What is the molarity of 2.3 mol of Kl dissolved in 0.5 L of water

Nastasia [14]

Answer:

$4.6\,\,moL\,\,L^{-1}$

Explanation:

Molarity refers to a measure of concentration.

Molarity = moles of solute/Litres of solution

Molarity refers to number of moles of solute present in this solution.

In order to find a solution's molarity, use value for the number of moles of solute and the total volume of the solution expressed in liters

As molarity of 2.3 mol of Kl is dissolved in 0.5 L of water,

Molarity = $\frac{2.3}{0.5} =4.6\,\,moL\,\,L^{-1}$

4 0

2 years ago

Which of the following would have the highest buffer capacity?

Mrrafil [7]

Answer:

1.25 M HCO₃⁻ / 1.25 M CO₃²⁻

Explanation:

Buffer capacity refers to the amount of a strong acid or base required per liter of the buffer to change its pH by one. This amount is directly related to the concentration of the conjugate acid-base pair in the buffer since the buffer pair neutralizes the strong acid or base.

Thus, the highest buffer capacity is found in the solution that has the highest concentration of the conjugate acid-base pair, which is 1.25 M HCO₃⁻ / 1.25 M CO₃²⁻ .

7 0

2 years ago

A yellow tulip and a red tulip are _____.

irina1246 [14]

Answer:

variations of the same species

Explanation:

hope this helps have a good day

7 0

2 years ago

Read 2 more answers

A hot air balloon is filled with 15 moles helium gas and 5 moles nitrogen gas. What is the volume of the balloon at 1.01 atm and

kvasek [131]

<u>Given:</u>

Moles of He = 15

Moles of N2 = 5

Pressure (P) = 1.01 atm

Temperature (T) = 300 K

<u>To determine:</u>

The volume (V) of the balloon

<u>Explanation:</u>

From the ideal gas law:

PV = nRT

where P = pressure of the gas

V = volume

n = number of moles of the gas

T = temperature

R = gas constant = 0.0821 L-atm/mol-K

In this case we have:-

n(total) = 15 + 5 = 20 moles

P = 1.01 atm and T = 300K

V = nRT/P = 20 moles * 0.0821 L-atm/mol-K * 300 K/1.01 atm = 487.7 L

Ans: Volume of the balloon is around 488 L

3 0

2 years ago