3.48 x 10^ -5
move the decimal point back to the first number that isn't zero, if the decimal is moved right 5 spaces, it will be 10^ -5 , if a number has a zero, such as 0.000104, it would be 1.04 x 10^ -4.
The answer is 28 years
At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079
t = ?
12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)
Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
Yes this is a correct statement.
Answer:
20
Step-by-step explanation:
All you need to do is find the highest number in this table. In this instance, the answer is 20.
From the equation of a line;
y=mx+c
m=2
y=2x+c
Replacing for;
y=1
x=3
1=2*3+c
1=6+c
c=1-6
c=-5
<span>y=2x-5</span>
