Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
Answer:
9 cherry, 6 blueberry
Step-by-step explanation:
lets do a table!
cherry | blueberry
----------------------------
3 2
6 4
9 6
When there are 2 blueberry, there are 3 cherry. 3 is 1 more than 2. When there are 4 blueberry, there are 6 cherry. 6 is 2 more than 4. When there are 6 blueberry, there aare 9 cherry. 9 is 3 more than 6.
Consecutive integers are 1 aparrt
they are
x,x+1,x+2,x+3
the 2nd and 4th sum is x+1 and x+3
sum is 34
x+1+x+3=34
2x+4=34
minus 4
2x=30
divide 2
x=15
x+1=16
x+2=17
x+3=18
the numbers are 15,16,17,18