The value (in cents) of the change in a purse that contains twice as many nickels as pennies, five more dimes than nickels, and

Question

2 years ago

6

as many quarters as dimes and nickels combined;
p = number of pennies

2 answers:

nexus9112 [7] · Answer 1 · 2022-06-07T02:46:43+03:00

Value of the pursue in cents: $131p+175$

Step-by-step explanation:

Let's call:

$p$ = number of pennies

The problem tells us that the pursue contains twice as many nickels as pennies, so the number of nickels is

$n=2p$

Also, the pursue contains five more dimes than nickels, so the number of dimes is

$d=n+5=2p+5$

And finally, the pursue contains as many quarters as dimes and nickels combained, so the number of quarters is

$q=d+n=(2p+5)+2p=4p+5$

The value of each type of coin is:

Penny: 1 cent

Nickel: 5 cents

Dime: 10 cents

Quarter: 25 cents

So, the total value of the pursue in cents is:

$1p+5n+10d+25q$

And substituting,

$=p+5(2p)+10(2p+5)+25(4p+5)=\\p+10p+20p+50+100p+125=\\131p+175$

So, this is the value of the change in the pursue in cents.

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kap26 [50] · Answer 2 · 2022-06-07T03:47:10+03:00

kap26 [50]2 years ago

8 0

Answer:

its d for online schoo

Step-by-step explanation: