X = 3y - 6....so sub 3y - 6 in for x in the other equation
2(3y - 6) - 4y = 8
6y - 12 - 4y = 8
2y = 8 + 12
2y = 20
y = 20/2
y = 10
x = 3y - 6
x = 3(10) - 6
x = 30 - 6
x = 24
solution is (24,10)
Answer:
For t=3 sec the velocity change from positive to negative
Step-by-step explanation:
we have
This is the equation of a vertical parabola open downward (the leading coefficient is negative)
where
s(t) is the distance in feet
t is the time in seconds
We know that
To find out when the velocity change from positive to negative, we need to determine the turning point of the quadratic equation
The turning point of the quadratic equation is the vertex
so
Convert the quadratic equation into vertex form
Factor -16
Complete the square
Rewrite as perfect squares
The vertex is the point (3,244)
therefore
For t=3 sec the velocity change from positive to negative
Answer:
6 6/8 OR 6 3/4
Step-by-step explanation:
2 5/8 +4 1/8
6 6/8
SImplify= 6 3/4
Given:
The given function is:
The graph of the function is given.
To find:
The end behavior of the given function.
Solution:
We have,
From the given graph it is clear that the function approaches to -4 at x approaches negative infinite and the function approaches to negative infinite at x approaches infinite.
as
as
Therefore, the end behaviors of the given function are:
as
as