Assuming that is a 24 the answer would be 24[10] = 240 but if that is the question 2 and the number is just 4 the answer is just 40
Answer:
c
Step-by-step explanation:
Answer:
x = 45, y = 5
Step-by-step explanation:
It is given that two lines form a linear pair with equal measures. Therefore, the angle between the two lines will be 90. Now, according to the question,
2x + 20y - 10 =90
2x+20y = 100
x + 10y = 50
And
2x = 20y-10
x = 10y -5
x - 10 y = -5
Now, adding x + 10y = 50 and x - 10y =-5, the value of x can be found. The required value will be:
x + 10y =50
x - 10y = -5
------------------
x = 45
Therefore, the value of y after substitution of the value of x in one of the equations will be:
90 = 20y - 10
20 y = 100
y = 5
Hence, the required value of x and y are 45 and 5 respectively.
Answer:
<h3>
The width (side perpedicular to the barn):
<u>x = 8 m</u></h3><h3> The lenght (side parallel to the barn):
<u>y = 16 m</u> </h3>
Step-by-step explanation:
x - the width of the barn
She has 32 m of fencing so for the lenght remain (32-2x) m of fencing:
y = 32 - 2x
Area of the fencing: A = x•y
A(x) = x•(32 - 2x)
A(x) = -2x² + 32x ← quadratic function
The maximum value of quadratic function occurs at:
a = -2, b = 32
32-2x = 32 - 2•8 = 16
Using the normal distribution, it is found that the probability is 0.16.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, the mean and the standard deviation are given by, respectively, .
The proportion of students between 45 and 67 inches is the p-value of Z when <u>X = 67 subtracted by the p-value of Z when X = 45</u>, hence:
X = 67:
Z = -1
Z = -1 has a p-value of 0.16.
X = 45:
Z = -8.3
Z = -8.3 has a p-value of 0.
0.16 - 0 = 0.16
The probability is 0.16.
More can be learned about the normal distribution at brainly.com/question/24663213