Can I use dis... do u know how to use dis?
Given the position function <em>s(t)</em>, you can get the acceleration function by differentiating <em>s</em> twice:
velocity = <em>s'(t)</em> = -5 sin(<em>t </em>) + 3 cos(3<em>t</em> )
acceleration = <em>s''(t)</em> = -5 cos(<em>t</em> ) - 9 sin(3<em>t</em> )
Then when <em>t</em> = <em>π</em>, the particle's acceleration is
<em>s''(π)</em> = -5 cos(<em>π</em>) - 9 sin(3<em>π</em>)
… = -5 • (-1) - 9 • 0 = 5
Step-by-step explanation:
option A i think
hope it helps
Answer:
200?
Step-by-step explanation:
its kinda simple but the 2 is in the hundreds place therefore it is 200.
hope it helped ;)
4x-2y=8 ==> y=2x-4 (to better show you what I mean)
2 lines are parallel if they have the same slope (m the coefficient of x).
So y=mx + b // y =2x-4 means m=2 & y=mx + b, becomes y=2x + b.
Moreover they are telling us that this function passes by (-2,1), where -2 represents x & 1, represents y. To calculate b , replace x & y by their values:
y=2x+b ==> 1 = 2(- 2) + b==> 1 = -4 + b ==> b= 5. Finally the equation is
y=-2x+5
