I'm assuming this is x^2 + 3x - 4 and x(x^2 + 3x - 2)
1.) First distribute x(x^2 + 3x - 2) to get x^3 + 3x^2 - 2x.
2.) Because you are subtracting all the terms from x^3 + 3x^2 - 2x, it's the same thing as distributing -1 to x^2 + 3x - 4 and then adding it to x^3 + 3x^2 - 2x.
3.) -1(x^2 + 3x - 4) = -x^2 - 3x + 4
4.) Add (x^3 + 3x^2 - 2x) + (-x^2 - 3x + 4)
5.) x^3 + 2x^2 - 5x + 4 is your final answer.
Answer:
g(x) = 5 – x
Step-by-step explanation:
Answer:
A.) 90 clockwise
E.)270 Counter Clockwise
Step-by-step explanation:
A.) Ro, -90 Rotation about the origin (0,0) 90° clockwise
(x, y) ⇒ (y, -x)
(-1, 5) ⇒ (5, 1)
E.) Ro, 270 Counter Clockwise
(x, y) ⇒ (y, -x)
(-1, 5) ⇒ (5, 1)
Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
Answer:
14
Step-by-step explanation:
