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2 years ago

A hose fills a 10,000-gallon swimming pool at a rate of 10 gallons per minute. what is the domain and range?

Mathematics

1 answer:

defon2 years ago

4 0

Answer:

Domain: 0 minutes to time it takes to fill. Range: 0 to a 10,000 gallons

Step-by-step explanation:

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Solve r = 4/3(p-q) for p.

alekssr [168]

R =4/3 (p-q)
3 x r = 4 (p-q)
(3 x r)/4 = p - q

(3 x r)/4 - q = p

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2 years ago

- 5 - 2 (a - b) + 2 (a - b) -3 (a - b) + 3 = ?

zzz [600]

Collect like terms and you'll get -2 - 3(a - b)

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2 years ago

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Which of the following is the solution for 6x + 3 ≤ 27

postnew [5]

Answer:

x ≤ 4

Step-by-step explanation:

6x + 3 ≤ 27 subtract 3 both sides

6x ≤ 24 divide 6 both sides

x ≤ 4 There's your answer

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2 years ago

The image shows the linear graph for a family that hired a babysitter for a day. The family gave the babysitter some money up fr

AleksandrR [38]

Answer:

I think it's A and C

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2 years ago

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A group of engineers is building a parabolic satellite dish whose shape will be formed by rotating the curve y=ax 2 about the y-

Setler79 [48]

Answer:

a = $\frac{1}{2}$ . Surface Area = $\frac{4}{3}$ $ft^{2}$ . and area of the Dish = $\frac{4}{3}$ $ft^{2}$ +pi $4^{2}$ = $\frac{4}{3}$ $ft^{2}$ +50.27=51.6 $ft^{2}$

Step-by-step explanation:

(1) Constant. y(x) = a $x^{2}$ that is the curve that we need to rotate around the y axis to get the parabola with diameter of 8 feet and 2 meter depth that statement is translated in mathematics as x = -4 to 4 and y = 0 to 2.

y max = 2, x max = 4 setting up a equation with a unknown gives

2=a4 and a = $\frac{1}{2}$ .

so we have now.

y(x) = $\frac{1}{2}x^{2}$ (Done with solving for a Constant).

(2) Surface Area.

Setting Up surface integral.

(i) range in x = 0 to 4.

(ii) range in y = 0 to 2.

integral is.

Integral(0-2)[{integral[(0-4) $\frac{1}{32}$ $x^{2}$ ]}]dy

Evaluating this integral gives. $\frac{4}{3}$ $ft^{2}$ .

and area is surface area + area of the circle with 8ft diameter.

= $\frac{4}{3}$ $ft^{2}$ +pi $4^{2}$ = $\frac{4}{3}$ $ft^{2}$ +50.27=51.6 $ft^{2}$ ...

Note the Difference between area and aurface area.!

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2 years ago