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2 years ago

Calculate the molar mass of cacl2

Chemistry

1 answer:

kirza4 [7]2 years ago

6 0

Answer:

$\boxed {\boxed {\sf 110.98 \ g/mol}}$

Explanation:

The molar mass is the mass of a substance in grams per mole.

To find it, add the mass of each element in the compound. These masses can be found on the Periodic Table.

The compound given is:

$CaCl_2$

The compound has 1 Ca (calcium) and 2 Cl (chlorine).

Mass of Calcium

The molar mass of calcium is 40.08 g/mol
There is only one atom of Calcium in CaCl₂, so the number above is what we will use.

Mass of Chlorine

The molar mass of chlorine is 35.45 g/mol
There are two atoms of chlorine in CaCl₂, therefore we need to multiply the molar mass by 2.
35.45 * 2= 70.9 g/mol

Molar Mass of CaCl₂

Now, to find the molar mass, add the molar mass of 1 calcium and 2 chlorine.
40.08 g/mol + 70.9 g/mol =110.98 g/mol

The molar mass of CaCl₂ is <u>110.98 grams per mole. </u>

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The reaction a(g) + 2b(g) c(g) was allowed to come to equilibrium. the initial amounts of reactants placed into a 5.00 l vessel

earnstyle [38]

Answer is: Kc for reaction is 16.66.
Chemical reaction: A + 2B ⇄ C.
c₀(A) = 1 mol ÷ 5 L; initial concentration of A.
c₀(A) = 0,2 mol/L.
c₀(B) = 1,8 mol ÷ 5 L; initial concentration of B.
c₀(B) = 0,36 mol/L.
c(B) = 1 mol ÷ 5 L.
c(B) = 0,2 mol/L; equilibrium concentration of B.
From chemical reaction: n(A) : n(B) = 1 : 2.
n(A) = 0,8 mol ÷ 2 = 0,4 mol.
c(A) = (1 mol - 0,4 mol) ÷ 5 L.
c(A) = 0,12 mol/L; equilibrium concentration of A.
n(C) : n(B) = 1 : 2.
n(C) = 0,4 mol.
c(C) = 0,4 mol ÷ 5 L.
c(C) = 0,08 mol/L; equilibrium concentration of C.
Kc = 0,08 mol/L ÷ ((0,2 mol/L)² ·0,12 mol/L).
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5 0

3 years ago

Danny lowers the sails on his boat. He paddles upstream at 19 km/hr. The current is still running downstream at 15 km/hr. What i

klio [65]

Answer:

You would need to multiply.

Explanation:

Multiply the numbers separately.

SO do 19x15 and see what you get.

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1 year ago

According to the label on a bottle of concentrated hydrochloric acid, the contents are 36% by mass and have a density of 1.138g/

elixir [45]

Answer:

1.42 Kg of NaHCO3

Explanation:

From

Co= 10 pd/M

Where;

Co= concentration of the stock solution of acid

p= percentage of raw acid = 36%

d= density of the acid= 1.138g/mL

M= molar mass of the acid= 36.5 g/mol

Co= 10 × 36 × 1.138/36.5

Co= 11.22 M

Number of moles of acid= CV = 11.22 M × 1.508 L= 16.9 moles

The reaction equation is;

NaHCO3(aq)+HCl(aq)→NaCl(aq)+H2O(l)+CO2(g)

If 1 mole of NaHCO3 reacts with 1 mole of HCl

Then 16.9 moles of HCl reacts with 16.9 moles of NaHCO3

Hence 16.9 moles of NaHCO3 is required to neutralize the HCl.

From

n= m/ M

Where;

n= number of moles = 16.9

m= mass of NaHCO3= ??

M= molar mass of NaHCO3= 84.007 g/mol

m= n× M/1000

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2 years ago

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Answer:

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2 years ago

A solution of ammonia and water contains 2.60×1025 water molecules and 6.90×1024 ammonia molecules. how many total hydrogen atom

marshall27 [118]

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2.07*10²⁵ + 5.20 *10²⁵ =7.27*10²⁵ atoms of H altogether.

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2 years ago