Answer:
2 + 3i, midpoint is (2,3)
Step-by-step explanation:
we need to find the midpoint between (-1+9i) and B=(5-3i)
To find the midpoint of two points (a+bi) and (c+di) in a complex plane,
we apply formula
A = (-1+9i) and B=(5-3i)
Midpoint for AB is
2 + 3i , so midpoint is (2,3)
The range is the output of the function, and there are many ways to find it and write it. Let's find it first by plugging in all the domain values (domain means input) into the function:
We have all of our values. We can either write the range as:
{
}
or, subtract the smallest value from the largest one:
So, there are those ways to write it, there are more, but I think you should stick with the first way because that's how the problem was presented to you. If you have any questions, hmu!
(x - 1)(x - 2)(x + 2)
note that the sum of the coefficients 1 - 1 - 4 + 4 = 0
thus x = 1 is a root and (x - 1 ) is a factor
dividing x³ - x² - 4x + 4 by (x - 1)
x³ - x² - 4x + 4 = (x - 1)(x² - 4 ) (note (x² - 4 ) is a difference of squares )
x³ - x² - 4x + 4 = (x - 1)(x - 2)(x + 2)
(x - 1)(x - 2)(x + 2 ) =0
x - 1 = 0 ⇒ x = 1
x - 2 = 0 ⇒ x = 2
x + 2 = 0 ⇒ x = - 2
solutions are x = 1 or x = ± 2
60 onces is 15lbs so then i beleve you have 11lbs too much