The answer I believe would be 2Y + 3x=6
When x = 1:
1³ + 1 - 3 = -1
When x = 2:
2³ + 2 - 3 = 7
Since f(x) = x³ + x - 3 is continuous, it follows from the intermediate value theorem that for some c in the interval (1, 2), we have f(c) = 0, since f(1) < 0 < f(2).
Answer:
Yes, (6, -2) is a solution to the given system of equations.
Step-by-step explanation:
Please write y = –1/6 x − 1 y = 1/6 x − 3 as follows, for greater clarity:
y = (–1/6)x − 1
y = (1/6)x − 3
Let's actually solve this system:
y = (–1/6)x − 1
y = (1/6)x − 3
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2y = -4, or y = -2
Now find x. Arbitrarily we choose to use the first equation for this purpose:
y = (-1/6)x - 1. We set y = -2 and find x: -2 = (-1/6)x - 1
Combining the constants, we get -1 = (-1/6)x, or 6 = x
Yes, (6, -2) is a solution to the given system of equations.
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Answer:
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Given:
Find:
Solution: Since we know that a is greater than b this means that no matter if we subtract or add a constant to both sides a would stay greater than b. Therefore, this would give us the expression of a - c > b - c.