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2 years ago

Write an equation in slope-intercept form for the line that passes through the

2 answers:

6 0

Make slope intercept
3x - y = 5
3x = y + 5
y = 3x - 5
Parallel = same slope
Slope = 3
Y = 3x + b
Plug in the point
-2 = 3(-1) + b
-2 = -3 + b, b = 1

Solution: y = 3x + 1

Reil [10]2 years ago

3 0

Answer:

y = 3x + 1

Step-by-step explanation:

the slope of the line of the given equation can bé find in this way: -a/b, where a is the number that multiplies x and b is the number that multiplies y

m = -3/-1 = 3

two parallel lines have the same slope, so also the line that we are a searching has m=3

now we can use this formula

y-y1 = m(x-x1) where y1 and x1 indicate the coordinates of the given point

y-(-2) = 3 (x-(-1)

y+2 = 3x + 3

y = 3x + 3-2

y = 3x + 1

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2 years ago

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2 years ago

I NEED HELP ASAP!!!! PLEASE HELP!!!

IRISSAK [1]

Answer:

y= 2x-3 m=2 b= -3

Step-by-step explanation:

we distribute 2(x-2)

y-1 = 2(x-2)

y-1 = 2x-4

then add one to both sides

y-1= 2x -4

+1 +1

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6 0

2 years ago

Solve for x. 5 = − 3 9 x

IgorLugansk [536]

Answer:

x = -5/27

Step-by-step explanation:

5 = − 3 · 9x; x = -5/27

6 0

2 years ago

Rationalize the denominator and simplify. StartFraction 5 minus StartRoot 3 EndRoot Over 4 plus 2 StartRoot 3 EndRoot EndFractio

nasty-shy [4]

Answer:

$\frac{13-7\sqrt{3}}{2}$

Step-by-step explanation:

We need to rationalize the denominator of $= \frac{5-\sqrt{3}}{4+2\sqrt{3}}$ . For rationalizing we multiply the equation by $\frac{4-2\sqrt{3}}{4-2\sqrt{3}}$

So, solving

$= \frac{5-\sqrt{3}}{4+2\sqrt{3}}*\frac{4-2\sqrt{3}}{4-2\sqrt{3}} \\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{4+2\sqrt{3}*4-2\sqrt{3}}\\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{(4)^2-(2\sqrt{3})^2}\\= \frac{5(4-2\sqrt{3})-\sqrt{3}(4-2\sqrt{3})}{16-(4*3)}\\=\frac{20-10\sqrt{3}-4\sqrt{3}+2*3}{16-12}\\=\frac{20+6-14\sqrt{3}}{4}\\=\frac{26-14\sqrt{3}}{4}\\= \frac{2(13-7\sqrt{3})}{4}\\=\frac{13-7\sqrt{3}}{2}$

5 0

2 years ago