The area of the square is obtained by taking the square of the length of one side. Since it is said that the area of the square is less than 100 m^2, taking the square root of that where: sqrt (100) = 10, the side of that square should be less than 10 as well. Among the choices, D. 0 <y <10 (where y = length of side of square) is the correct answer.
Given:
In a two-digit number, the tens digit is 5 less than the units digit.
The number itself is five more than three times the sum of its digits.
To find:
The number.
Solution:
Let the two digit number is ab. So,
Tens digit is 5 less than the units digit.
...(i)
The number itself is five more than three times the sum of its digits.
...(ii)
Using (i) and (ii), we get
Putting b=8 in (i), we get
Therefore, the required number is 38.
Answer:
Step-by-step explanation:
Bottom triangle
Area = b * height
b = 4 + 4 = 8 cm
h = 5.75
Area = 1/2 * 5.75 * 8
Area = 23 cm^2
Trapezoid
b1 = 8
b2 = 4
h = 2
Area = (b1 + b2)*h/ 2
Area = (8 + 4)*2 /2
Area = 12
Total area = 23 + 12
Total area = 35
Step-by-step explanation:
here's the answer to your question
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