Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
Answer:
1872
Step-by-step explanation:on edge
Caroline, Colin & Sarah share some money.Caroline will get 
when Caroline, Colin & Sarah share some money.
<h3>What is the ratio?</h3>
The ratio defined as the sharing of the two or three things or it represent that one thing or number is how many times to the other.
One part is excluded in the problem. That part is:
"Caroline gets 
of the money."
If Caroline gets 1/9th, then remaining is:
Colin and Sarah share in ratio 3 is to 1, that means 3 + 1 = 4 parts...
8/9th in 4 parts means, each part is:
We know Colin gets "3" parts of the total, each part is (2/9)th, so 3 parts would be:
Colin gets money when three of them share money.
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Answer:
3 flowers are in Julias bouquet
Step-by-step explanation:
120 divided by 40 = 3
The two angles are x and 9x/5
<h3 /><h3 />
Let the two angles we require be x and y.
<h3 /><h3>Ratio of both angles</h3>
We have that the ratio of both angles are x:y
Since both angles are in the ratio 5:9, we have that,
x:y = 5:9
⇒ x/y = 5/9
<h3 /><h3>Value of the other angle</h3>
So, we Make y subject of the formula
Multiplying both sides by y, we have
y × x/y = 5/9 × y
x = 5y/9
Multiplying both sides by 9, we have
9 × x = 5y/9 × 9
9x = 5y
Dividing both sides by 5, we have
9x/5 = 5y/5
y = 9x/5
So, the two angles are x and 9x/5
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