Step-by-step explanation:
LHS= sin 3x/sin x - cos 3x/cosx
Taking LCM,
<u>=</u><u>sin3xcosx- cos3xsinx</u>
sinxcosx
<u>=</u><u>sin(3x-x)</u>
sinxcosx
= <u>2sin2x</u>
2sinxcosx
=<u> </u><u>2sin2x</u><u> </u>
sin2x
=2
= RHS.
Proved.
Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer
Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
-2x - 6. -2x -6
0 = x^2 + 3x. Factor
0 = x (x + 3)
Solve: x = 0. x + 3 = 0. ——> x = -3. Substitute into one original equation to get y value for
y = 2x + 6.
y = 2(0) + 6. y = 2(-3) + 6
y = 6. y = -6 + 6 —-> y = 0
(0 , 6) And. (-3 , 0)
#3) 9/3= 3
90/3=30
900/3=300
9.000/3=3.3000
#4)1/2, 2/3, 2/5, 3/4
Answer:
Step-by-step explanation:
y = -4x^2 + 4x + 6
Factor out the leading coefficient:
y = -4(x^2 - x) + 6
Complete the square:
y = -4(x^2 - x + (½)^2) + 4(½)^2 + 6
= -4(x-½)^2 + 7
When asked to evaluate, you have to plug in the given value of n (in this case), into the given equation.
n/6 = ?
In order to find out ?, we need to know what n is.
Well, n = 12
So, plug in 12 for n
n/6 would now be written as 12/6 in order to be evaluated
Now, simplify.... What you get for 12/6 is the answer
