Answer: I'm not sure if I'm right but i think it is A.) or maybe C.) I really don't know it could be any So please don't get mad at me if you get it wrong because of me
Step-by-step explanation:
Answer:
2 solutions
Step-by-step explanation:
I like to use a graphing calculator to find solutions for equations like these. The two solutions are ...
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To solve this algebraically, it is convenient to subtract 2x-7 from both sides of the equation:
3x(x -4) +5 -x -(2x -7) = 0
3x^2 -12x +5 -x -2x +7 = 0 . . . . . eliminate parentheses
3x^2 -15x +12 = 0 . . . . . . . . . . . . collect terms
3(x -1)(x -4) = 0 . . . . . . . . . . . . . . . factor
The values of x that make these factors zero are x=1 and x=4. These are the solutions to the equation. There are two solutions.
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<em>Alternate method</em>
Once you get to the quadratic form, you can find the number of solutions without actually finding the solutions. The discriminant is ...
d = b^2 -4ac . . . . where a, b, c are the coefficients in the form ax^2+bx+c
d = (-15)^2 -4(3)(12) = 225 -144 = 81
This positive value means the equation has 2 real solutions.
Beacuse <span>A square by definition is a "plane figure having four equal sides." Rectangles' sides are not equal and hence cannot be a square.
A rectangle by definition is a "four-sided plane figure with 4 right angles" - which also implies that a square can be a rectangle because it is also a four-sided plane figure with 4 right angles...... hope this helps</span>
Answer:
The first equation
Step-by-step explanation: