Answer:
20 gallons of water is leaked after an hour.
Step-by-step explanation:
Water is leaking at a constant rate of 1/3 gallon per minute.
a) We have to write a linear equation in two variables that show the amount of water, w, in gallons, that is leaked from the faucet after t minutes.
So, the equation is ......... (1) (Answer)
b) Now, if t = 1 hour i.e. 60 minutes, then from equation (1) we can write
gallons.
Therefore, 20 gallons of water is leaked after an hour. (Answer)
Answer:
Step-by-step explanation:
Answer:
20748
Step-by-step explanation:
546 times 38
Answer:
Function H h(t) = -6.1 + 19t - 55
Step-by-step explanation:
Let t = 1
<u>Function F</u>
h(t) = 6.1t^2 + 19t - 54.4
h(1) = 6.1(1)^2 + 19(1) - 54.4
h(1) = 6.1 + 19 - 54.4
h(1) = -29.3
<u>Function G</u>
h(t) = -24.1t^2 + 2.8
h(1) = -24.1(1)^2 + 2.8
h(1) = -24.1 + 2.8
h(1) = -21.3
<u>Function H</u>
h(t) = -6.1t^2 + 19t - 55
h(1) = -6.1(1)^2 + 19(1) - 55
h(1) = -6.1 + 19 - 55
h(1) = -42.1
<u>Function J</u>
h(t) = -6.1t^2 + 19t + 0.99
h(t) = -6.1(1)^2 + 19(1) + 0.99
h(t) = -6.1 + 19 + 0.99
h(t) = 13.89