To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
Answer:
4+11a+8b
Step-by-step explanation:
1) 4+3a+2b+6b+5a+3a
2) 3a+3a+5a=11a. 2b+6b=8b
Answer:
-6x-10y
Step-by-step explanation:
Multiply -2 by everything in parenthesis
Answer:
360°
Step-by-step explanation:
Each of the two triangles have 3 angles that add up to 180°.
So,
180° + 180° = 360°
The sum of the angles of a quadrilateral is 360°