First set up a linear equation and using the x and y values in the table see if it solves.
It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)
Using the quadratic formula y = ax^2 +bx +c
Build a set of 3 equations from the table:
C is the Y intercept ( when X is 0), this is shown in the table as 6
Now we have y = ax^2 + bx + 6
-2.4 =4a-2b +6
1.4 = a-b +6
Rewrite the equations
a=b/2 -2.1
1.4 = b/2-2.1 +6
b = 5
a = 5/2 -2.1 = 0.4
replace the letters to get y = 0.4x^2 + 5x +6
27.8 × 9.6 is equal to <span>266.88</span><span>
So, the closest would be A. 280.</span>
This is 6P4
the number of permutations of 4 from 6. 6! / 2!
= 6*5*4*3* 2 / 2 = 360
the length is given and i got the width as 8 so you just add up all the sides and i got 40
Answer:
C) 22 pi
Step-by-step explanation:
Here the diameter of the circle = 24.
Therefore, radius of the circle = 24/2 = 12 ft
Here we have to use the formula to find the arc length.
Arc length = (central angle / 360) * 2*pi*r
Central angle ABC = 360 - 30 = 330 degrees and radius (r) = 12
Now plug in these values in the formula, we get
Arc length ABC = (330/360) *2*pi*12
Now we have to simplify it.
= 11/12 *2 *pi*12
= 11*2*pi
Arc length of ABC = 22pi
Therefore, the answer is C) 22 pi
Hope you will understand the concept.
Thank you.
