All categories

2 years ago

Please Help This is due soon!

Mathematics

2 answers:

Sonja [21]2 years ago

5 0

They are congruent ur welcom

Gnesinka [82]2 years ago

3 0

Yes there congruent and a counter clockwise rotation would prove so

You might be interested in

Can someone help me with one question please And fast

m_a_m_a [10]

Answer:

equal to 4

Step-by-step explanation:

..................

5 0

2 years ago

Read 2 more answers

A bag contains 5 blue, 4 red, 7 black and 2 white marbles. What is the probability of selecting a marble that is NOT white?

iogann1982 [59]

Answer:

8/9 (simplified)

Step-by-step explanation:

Total marbles = 18

Total of marbles <em>not</em> white = 16

Numerator = 16 / Denominator = 18

= 16/18

= 8/9 (simplified)

3 0

2 years ago

Read 2 more answers

What is the measure of ∠F? Irregular quadriateral. Reading clockwise, the angles are labeled one hundred thirty-two degrees, six

Delvig [45]

Total of all angles should equal 360 degrees. So 360-132-68-66=94, angle F is 94 degrees.

5 0

2 years ago

Brainliest if its right

ddd [48]

Answer:

Step-by-step explanation:

28=Diameter

Radius= D/2

=14

6 0

1 year ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

2 years ago