What is the Deepest point of the ocean and where is it?

Physics

2 answers:

qaws [65]2 years ago

5 0

Answer:

marinas trench in Pacific Ocean

<h2>mark it as brainliest</h2>

Rashid [163]2 years ago

3 0

Explanation:

Located in the western Pacific Ocean, the Marina Trench

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A book falls off a shelf that is 10.0 m tall. What is the velocity at which the book hits the ground?

Elena L [17]

Answer:

14 m/s

Explanation:

The motion of the book is a free fall motion, so it is an uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. Therefore we can find the final velocity by using the equation:

$v^2 = u^2 + 2gd$

where

u = 0 is the initial speed

g = 9.8 m/s^2 is the acceleration

d = 10.0 m is the distance covered by the book

Substituting data, we find

$v=\sqrt{0^2 + 2(9.8 m/s^2)(10.0 m)}=14 m/s$

8 0

2 years ago

The process of sediments being compacted and cemented to form sedimentary rocks is called

crimeas [40]

Answer:

Lithification is the answer.

8 0

2 years ago

What is the maximum speed when the conditions are mass =450 kg, initial height= 30 m, and the roller coaster is initially at res

Zarrin [17]

Answer:

B. 24.2 m/s

Explanation:

Given;

mass of the roller coaster, m = 450 kg

height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster due to its height is given by;

$P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J$

$P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)$

$K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\ v_{max} = 24.2 \ m/s$