Answer:
Step-by-step explanation:
Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.
we have to find the length of AB.
Let the side of square i.e AB is x units.
As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°
⇒ CP||MP||AB
In ΔMNP and ΔCND
∠NCD=∠NMP (∵ corresponding angles)
∠NDC=∠NPM (∵ corresponding angles)
By AA similarity rule, ΔMNP~ΔCND
Also, ΔKAP~ΔKPM by similarity rule as above.
Hence, corresponding sides are in proportion
Adding above two, we get
⇒
⇒
⇒
⇒
⇒
⇒
If we multiply the bottom equation by 2 and move x to the right, it becomes:
4y = 2x-38
Now we can substitute it for the 4y in the top equation:
3x + (2x-38) = -23 => 5x = -23+38 => 5x = 15 => x=3
Then 4y = 2*3-38 => y = -8
So the solution is (3,-8)
Step-by-step explanation:
Explanation is in the attachment
hope it is helpful to you
8x²+3y²=24
8x²+3y²-24=0
Let x be 1 ,
Therefore
8+3y²-24=0
3y²-16=0
3y²=16
y²=16/3
y=4/1.7
y=40/17
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Answer: n = 4
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