Answer:
- As x approaches negative infinity, f(x) approaches negative infinity
Step-by-step explanation:
<u>Given function</u>
- f(x)= x^3 + 2x^2 - 5x - 6
<u>Finding zero's</u>
- x^3 + 2x^2 - 5x - 6 = 0
- x^3 - 2x^2 + 4x^2 - 8x +3x - 6 =
- (x - 2)(x^2 + 4x + 3) =
- (x - 2)(x^2 + x + 3x + 3) =
- (x - 2)(x(x + 1) + 3(x + 3)) =
- (x - 2)(x + 1)(x + 3)
<u>Zero's are</u>
<em>See the graph attached</em>
<u>Correct end behavior as per graph:</u>
- As x approaches negative infinity, f(x) approaches negative infinity
If there is more information then you should use it but if that is then yes it is possible if you think hard enough.
Hey there!
The answer to your question is 313/495
To solve this, let's use the equation x = .6323232...
We want to get <u>ONLY THE REPEATING PART</u> on one side of the decimal, so we can multiply the equation by 101:
100x = 6.323232...
Now, we can take the original equation and subtract it from the new equation:
100x = 63.232...
x = .632...
99x = 62.6
Now, divide both sides by 99.
x = 62.6/99
Simplify the fraction:
x = 313/495
Good luck! Hope it helps, and have a great day!
Answer:
2nd, 3rd and the last one
10 quarters....5 nickels......15 in total
probability of picking a nickel first is 5/15 which reduces to 1/3
without replacement
probability of picking a quarter next is 10/14 which reduces to 5/7
probability of both is : 1/3 * 5/7 = 5/21 <==
There are dependent events being that u didn't replace what u picked <==